Initializing variables with initializers in Java. However, when you read an unitilised value it will be The addition of the method only prevents the compiler from detecting you are trying to use a variable before it was initialised.You could test if the compiler ignores the non-executable method by putting some print statements in itthis shows us that the method is executed but because second is not yet initialized it returns 0 the first time.Let's try to understand things from JVM perspective:Here, as part of loading - static members are getting executed in order of occurrence. 5,157 6 6 gold badges 20 20 silver badges 40 40 bronze badges. For example, creating a set containing n elements involves constructing it, storing it in a variable, invoking add() method on it n times, and then maybe wrapping it … The initialization (i.e. Create a reference to that memory locations. Java Static Method. So I have the static member precision and a public static method to set its value in my class (the code below is stripped down a lot). java initialization static-methods.

site design / logo © 2020 Stack Exchange Inc; user contributions licensed under If you write 2 static methods in your code, while executing java program class loader first load the class and then look for how many static methods in program ,let us assume in our program we have 2 , so it’s create memory for those in static area. ... Browse other questions tagged c++ initialization declaration static-methods static-members or ask your own question. @Eran I was just checking it out and everything is as you wrote but for one thing - "which happens when your application first accesses any member (constructor, static method, static variable)". A static method can be invoked without the need for creating an instance of a class. the execution of the static declarations and static initialization blocks) will occur when the class is loaded, which happens when your application first accesses any member (constructor, static method, static variable) of your class. 4. If you apply static keyword with any method, it is known as static method. Stack Overflow works best with JavaScript enabled Java is often criticized for its verbosity.

By using our site, you acknowledge that you have read and understand our your coworkers to find and share information. I wonder how java initialize these static variables.

Method Try placing a static block in the code & put some debug points - you will see it yourself.Thanks for contributing an answer to Stack Overflow! I read lots of discussions available on the net but still I am confused. In case of After Step 2 you are actually initializing the array i.e putting the values in it.If you want to initialize it when the class is loaded, then you should use the Initializing a static member in the constructor defeats the purpose of static members, since they don't belong to any instance, and each new instance you'll create will override the value of your static array.You should either initialize the static variable when it's declared or in a static initialization block.The initialization (i.e. These all process running under JRE. I had a @MichałSchielmann It's possible that if you define a final static variable, the compiler replaces it with its constant value where ever it is accessed, and therefore the class is not loaded when you access it. Step 2 is be the initialization step, right? The initialization of array means putting things into it that you are doing after step 2.Then what happens in step 1 "when the class is loaded"?when the class is loaded all static variables are initialized with their default values. This is an unsolvable halting problem in the general case. @Bishal "loaded" means what I wrote in the last sentence. ... Java: when to use static methods. Sample share | improve this question | follow | asked Jul 24 '12 at 12:49. lynks lynks. By clicking “Post Your Answer”, you agree to our To subscribe to this RSS feed, copy and paste this URL into your RSS reader. 2) Java static method. Otherwise, it assigns whatever value is set as its initial value.Thanks for contributing an answer to Stack Overflow!